Borussia Dortmund vs PSV Prediction Match Details
Borussia Dortmund will host PSV Eindhoven for the second leg of their round-of-16 UEFA Champions League clash after a thrilling 1-1 draw in the first leg. The game is set to take place at Signal Iduna Park in Dortmund
Borussia Dortmund Preview & Form
Dortmund enters this game in average form, having won two, drawn two, and lost one of their last five games. In their most recent match, they secured a hard-fought 2-1 victory against Werder Bremen, with Donyell Malen and Jaden Sancho scoring goals to give Dortmund a comfortable 2-0 lead. However, Marcel Sabitzer’s red card just before halftime made things difficult for them. Despite being a man down, Dortmund managed to hold on for an important three points. Dortmund currently sits fourth in the Bundesliga with 47 points from 25 games.
In their last seven Champions League matches, Edin Terzic’s men have won three, drawn three, and lost just one game. During this run, they have managed to keep three clean sheets.
PSV Preview & Form
PSV Eindhoven is participating in the knockout stage of the UEFA Champions League for the first time since the 2015/16 season. In their last seven games in the tournament, the team has achieved two wins, four draws, and only one loss. In the first leg of their round-of-16 tie against Borussia Dortmund, PSV managed to secure a draw thanks to a second-half penalty converted by De Jong in the 58th minute.
The Dutch team is currently unbeaten in their last five matches, having won three and drawn two. In their most recent game, they secured a 1-0 victory against Go Ahead Eagles, with Sergiño Dest scoring the only goal of the match after just ten minutes.
Borussia Dortmund vs PSV Prediction Betting Tips
Borussia Dortmund has a remarkable track record in their previous two games played at Signal Iduna Park. In 2017, Dortmund won 4-1, and in 2002, they played a 1-1 draw. However, it is worth noting that in their last four matches, both teams have scored. We predict the match will see both teams score.